Simplifying Cube Roots: $\sqrt[3]{81x^7}$ Explained!

by Alex Johnson 53 views

In this article, we'll break down the process of simplifying the cube root expression 81x73\sqrt[3]{81x^7}. This topic falls under mathematics, specifically dealing with radicals and exponents. If you've ever felt confused about simplifying expressions with radicals, you're in the right place! We'll go through each step in a clear, easy-to-understand way. Let's dive in and make cube root simplification a breeze!

Understanding the Basics of Cube Roots

Before we jump into simplifying 81x73\sqrt[3]{81x^7}, it’s essential to understand what a cube root is and the properties that govern its behavior. Cube roots are a specific type of radical, and grasping the core concepts will make the simplification process much smoother. At its heart, a cube root is the inverse operation of cubing a number. Just as the square root of 9 is 3 because 32=93^2 = 9, the cube root of 8 is 2 because 23=82^3 = 8. In mathematical notation, the cube root is represented by the symbol 3\sqrt[3]{}. The small 3 above the radical sign indicates that we're looking for a number that, when multiplied by itself three times, gives us the number inside the radical. For example, 273=3\sqrt[3]{27} = 3 because 3Γ—3Γ—3=273 \times 3 \times 3 = 27. Another key concept to understand is the relationship between cube roots and exponents. Taking the cube root of a number is equivalent to raising that number to the power of 13\frac{1}{3}. So, x3\sqrt[3]{x} can also be written as x13x^{\frac{1}{3}}. This equivalence is incredibly useful when simplifying expressions, especially those involving variables and exponents. Moreover, it's crucial to remember that cube roots, unlike square roots, can handle negative numbers. For instance, βˆ’83=βˆ’2\sqrt[3]{-8} = -2 because (βˆ’2)Γ—(βˆ’2)Γ—(βˆ’2)=βˆ’8(-2) \times (-2) \times (-2) = -8. This is because a negative number multiplied by itself three times results in a negative number. In summary, understanding these fundamental principles of cube roots – their relationship to cubing, their notation, their connection to fractional exponents, and their ability to handle negative numbers – is vital for simplifying expressions like 81x73\sqrt[3]{81x^7}. These basics lay the groundwork for the more complex steps we’ll explore next.

Breaking Down the Expression 81x73\sqrt[3]{81x^7}

Now that we've covered the basics, let’s focus on how to break down the expression 81x73\sqrt[3]{81x^7} into smaller, more manageable parts. Breaking down this expression involves separating the numerical and variable components and then further factoring them into perfect cubes and remaining factors. This step is crucial for simplifying radicals effectively. First, consider the number 81. We need to find its prime factorization, which means expressing it as a product of its prime factors. The prime factorization of 81 is 3Γ—3Γ—3Γ—33 \times 3 \times 3 \times 3, or 343^4. Notice that we have three 3s, which make a perfect cube (33=273^3 = 27), and one remaining 3. This is important because we can take the cube root of a perfect cube. Next, let's look at the variable part, x7x^7. We need to determine how many perfect cubes of x are contained in x7x^7. Recall that when multiplying variables with exponents, we add the exponents. So, we want to find multiples of 3 that are less than or equal to 7. The largest multiple of 3 that fits this condition is 6. Therefore, we can rewrite x7x^7 as x6Γ—x1x^6 \times x^1, or simply x6Γ—xx^6 \times x. Here, x6x^6 is a perfect cube because it can be written as (x2)3(x^2)^3. Now that we have broken down both the numerical and variable parts, we can rewrite the original expression as 34x73=(33Γ—3)(x6Γ—x)3\sqrt[3]{3^4 x^7} = \sqrt[3]{(3^3 \times 3) (x^6 \times x)}. This separation allows us to see the perfect cubes clearly and prepares us for the next step, which involves extracting these perfect cubes from under the radical. By methodically breaking down the expression into its prime factors and identifying perfect cubes, we lay the groundwork for simplification. This process ensures that we address each component of the expression in a systematic way, making the overall simplification more straightforward.

Extracting Perfect Cubes from the Radical

With the expression 81x73\sqrt[3]{81x^7} broken down into (33Γ—3)(x6Γ—x)3\sqrt[3]{(3^3 \times 3) (x^6 \times x)}, the next step is to extract the perfect cubes from under the radical. Extracting perfect cubes involves using the property of radicals that states abn=anΓ—bn\sqrt[n]{ab} = \sqrt[n]{a} \times \sqrt[n]{b}. This property allows us to separate the radical into smaller, more manageable parts, specifically those that are perfect cubes. We can rewrite our expression as 33Γ—3Γ—x6Γ—x3=333Γ—33Γ—x63Γ—x3\sqrt[3]{3^3 \times 3 \times x^6 \times x} = \sqrt[3]{3^3} \times \sqrt[3]{3} \times \sqrt[3]{x^6} \times \sqrt[3]{x}. Now, we can simplify the terms that are perfect cubes. The cube root of 333^3 is simply 3 because, as we discussed earlier, the cube root is the inverse operation of cubing. Similarly, to find the cube root of x6x^6, we can think of it as (x2)3(x^2)^3. Therefore, x63=x2\sqrt[3]{x^6} = x^2. This is because when we raise a power to a power, we multiply the exponents, so (x2)3=x2Γ—3=x6(x^2)^3 = x^{2\times3} = x^6. Now we can substitute these simplified terms back into our expression: 3Γ—33Γ—x2Γ—x33 \times \sqrt[3]{3} \times x^2 \times \sqrt[3]{x}. We've successfully extracted the perfect cubes from under the radical, leaving us with the remaining factors still under the cube root. This step is crucial because it reduces the complexity of the radical expression. By identifying and extracting perfect cubes, we are essentially simplifying the expression to its most basic form within the constraints of radical simplification. This process highlights the power of understanding the properties of radicals and exponents in making mathematical expressions more manageable.

Simplifying the Remaining Expression

After extracting the perfect cubes, we are left with 3Γ—33Γ—x2Γ—x33 \times \sqrt[3]{3} \times x^2 \times \sqrt[3]{x}. The final step in simplifying 81x73\sqrt[3]{81x^7} is to combine the remaining terms under the radical and present the expression in its simplest form. Simplifying the remaining expression mainly involves multiplying the terms that are still under the cube root and writing the entire expression in a neat and organized manner. We have 33\sqrt[3]{3} and x3\sqrt[3]{x} left under the cube root. Using the property of radicals that states anΓ—bn=abn\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{ab}, we can combine these terms. This gives us 3Γ—x3\sqrt[3]{3 \times x}, which simplifies to 3x3\sqrt[3]{3x}. Now, we can rewrite the entire expression by bringing together the terms we extracted earlier and the simplified radical: 3Γ—x2Γ—3x33 \times x^2 \times \sqrt[3]{3x}. Typically, we write the terms outside the radical before the radical itself, so the simplified expression is 3x23x33x^2\sqrt[3]{3x}. This is the simplest form of the original expression 81x73\sqrt[3]{81x^7}. We have successfully removed all perfect cubes from under the radical, leaving only the simplest possible terms. This final simplification demonstrates the importance of combining like terms and presenting the result in a standard mathematical format. It also highlights the overall process of simplifying radicals, which involves breaking down the expression, extracting perfect powers, and then combining the remaining terms. By following these steps, we can transform complex expressions into more manageable and understandable forms. The result, 3x23x33x^2\sqrt[3]{3x}, is clear, concise, and fully simplified.

Conclusion

In conclusion, simplifying the expression 81x73\sqrt[3]{81x^7} involves a methodical process of breaking down the terms, extracting perfect cubes, and combining the remaining factors. We started by understanding the basics of cube roots and their properties. Then, we broke down 81 and x7x^7 into their prime factors and identified perfect cubes. Next, we extracted these perfect cubes from the radical. Finally, we combined the remaining terms to arrive at the simplified expression: 3x23x33x^2\sqrt[3]{3x}. This process not only simplifies the expression but also reinforces the fundamental principles of radicals and exponents. Understanding these concepts is crucial for tackling more complex mathematical problems. If you're looking to further enhance your understanding of radicals and exponents, exploring additional resources and practice problems is a great way to solidify your knowledge. For more in-depth explanations and examples, you might find valuable information on websites like Khan Academy's Algebra section.